Bodcaw, Arkansas

Bodcaw is a town in Nevada County, Arkansas, United States. The population was 154 at the 2000 census. It is part of the Hope Micropolitan Statistical Area.

Geography
Bodcaw is located at 33.55639°N, -93.40139°W (33.556740, -93.401286).

According to the United States Census Bureau, the town has a total area of 7.8 km² (3.0 mi²). 7.7 km² (3.0 mi²) of it is land and 0.1 km² (0.04 mi²) of it (1.32%) is water.

Demographics
As of the census of 2000, there were 154 people, 63 households, and 44 families residing in the town. The population density was 20.0/km² (51.6/mi²). There were 77 housing units at an average density of 10.0/km² (25.8/mi²). The racial makeup of the town was 98.70% White and 1.30% Black or African American. 1.30% of the population were Hispanic or Latino of any race.

There were 63 households out of which 30.2% had children under the age of 18 living with them, 58.7% were married couples living together, 7.9% had a female householder with no husband present, and 28.6% were non-families. 25.4% of all households were made up of individuals and 12.7% had someone living alone who was 65 years of age or older. The average household size was 2.44 and the average family size was 2.96.

In the town the population was spread out with 22.1% under the age of 18, 10.4% from 18 to 24, 21.4% from 25 to 44, 25.3% from 45 to 64, and 20.8% who were 65 years of age or older. The median age was 42 years. For every 100 females there were 111.0 males. For every 100 females age 18 and over, there were 103.4 males.

The median income for a household in the town was $24,375, and the median income for a family was $45,313. Males had a median income of $35,625 versus $28,125 for females. The per capita income for the town was $13,574. About 18.6% of families and 21.9% of the population were below the poverty line, including 28.6% of those under the age of eighteen and 6.9% of those sixty five or over.